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4x^2+1056.2x+11153.3=0
a = 4; b = 1056.2; c = +11153.3;
Δ = b2-4ac
Δ = 1056.22-4·4·11153.3
Δ = 937105.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1056.2)-\sqrt{937105.64}}{2*4}=\frac{-1056.2-\sqrt{937105.64}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1056.2)+\sqrt{937105.64}}{2*4}=\frac{-1056.2+\sqrt{937105.64}}{8} $
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